Golang算法之田忌赛马问题实现方法分析

package huawei

//Date：2015-8-14 15:43:11
import (
    "fmt"
    "io/ioutil"
    "sort"
    "strings"
)
//思路：用自己最强的(半数+1)个马和对手最弱的(半数+1)个马比赛
func Test11Base() {
    data, err := ioutil.ReadFile("DataFiles/huawei_test11.txt")
    checkError(err, "Reading file")
    strs := strings.Split(string(data), "n")
    index := 0
    for {
        count := strs[index]
        if count == "0" {
            break
        }
        teamA := convertToIntSlice(strings.Fields(strs[index+1]))
        teamB := convertToIntSlice(strings.Fields(strs[index+2]))
        if canWin(teamA, teamB) {
            fmt.Println("YES")
        } else {
            fmt.Println("NO")
        }
        index += 3
    }
}
//判断teamA是否能够胜利
func canWin(teamA []int, teamB []int) bool {
    sort.Ints(teamA)
    sort.Ints(teamB)
    length := len(teamA)
    tryCount := length/2 + 1
    for i := 0; i < tryCount; i++ {
        //A组最强的一半
        speedA := teamA[length-(tryCount-i)]
        //B组最弱的一半
        speedB := teamB[i]
        if speedA <= speedB {
            return false
        }
    }
    return true
}