Ajax请求PHP后台接口返回信息的实例代码

 
 
 

  昵称
  
 
 

  Email 
  
  
 
 

  留言内容
  
  
  Submit
 

 public function postMassage(Request $Request)
 {  
   $email  = $Request->email;
   $messages = $this->article_messages->where('email',$email)->first();
   if (!empty($messages)) {
   return response()->json(['status' => 'ok','code' => 400,'message' => '该邮箱已存在！换一个吧！',]);
   }
 }