PHP上传图片到数据库并显示代码如何实现

CREATE TABLE ccs_image (

 id int(4) unsigned NOT NULL auto_increment,

 description varchar(250) default NULL,

 bin_data longblob,

 filename varchar(50) default NULL,

 filesize varchar(50) default NULL,

 filetype varchar(50) default NULL,

 PRIMARY KEY (id)

)engine=myisam DEFAULT charset=utf8

  

  

  

  Document

<?php if (isset($_POST['submit'])) {

  $form_description = $_POST['form_description'];

  $form_data_name = $_FILES['form_data']['name'];

  $form_data_size = $_FILES['form_data']['size'];

  $form_data_type = $_FILES['form_data']['type'];

  $form_data = $_FILES['form_data']['tmp_name'];

   

  $dsn = 'mysql:dbname=test;host=localhost';

  $pdo = new PDO($dsn, 'root', 'root');

  $data = addslashes(fread(fopen($form_data, "r"), filesize($form_data)));

  //echo "mysqlPicture=".$data;

   

  $result = $pdo->query("INSERT INTO ccs_image (description,bin_data,filename,filesize,filetype)

         VALUES ('$form_description','$data','$form_data_name','$form_data_size','$form_data_type')");

  if ($result) {

    echo "图片已存储到数据库";

  } else {

    echo "请求失败,请重试";

<?php $id =2;// $_GET['id']; 为简洁,直接将id写上了,正常应该是通过用户填入的id获取的

  $dsn ='mysql:dbname=test;host=localhost';

  $pdo = new PDO($dsn,'root','root');

  $query = "select bin_data,filetype from ccs_image where id=2";

  $result = $pdo->query($query);

  $result = $result->fetchAll(2);

//  var_dump($result);

  $data = $result[0]['bin_data'];

  $type = $result[0]['filetype'];

  Header( "Content-type: $type");

  echo $data;