sql中取字符串中的数字语句

one:
declare @s varchar(20)
declare @i varchar(20)
set @i=''
set @s='新会员必须购买350元产品'
while PATINDEX ('%[0-9]%', @s)>0
begin
set @i=@i+substring(@s,PATINDEX ('%[0-9]%', @s),1)
set @s=stuff(@s,1,PATINDEX ('%[0-9]%', @s),'')
end
select @i
--
300

two:
declare @a table(id int identity(1,1),a varchar(100))
insert @a select '新会员必须购买350元产品'
union all select '新店首次定货必须满20000元'

select left(right(a,len(a)-patindex('%[0-9]%',a)+1),len(right(a,len(a)-patindex('%[0-9]%',a)+1))-1) from @a

create function fn_GetNum(@s varchar(8000))
returns varchar(8000)
as
begin
select @s = stuff(stuff(@s, 1, patindex('%[0-9, .]%', @s) - 1, ''),
patindex('%[^0-9, .]%', stuff(@s, 1, patindex('%[0-9, .]%', @s) - 1, '')),
len(@s), '')
return @s
end

declare @t table(s varchar(8000))

insert @t select 'aaa11112bbb'
union all select 'ccc212sss'
union all select 'sss21a'

select dbo.fn_GetNum(s) as result from @t

select substring(s,patindex('%[^0-9][0-9]%',s)+1,patindex('%[0-9][^0-9]%',s)-patindex('%[^0-9][0-9]%',s)) from @t

/*功能:获取字符串中的字母*/
CREATE FUNCTION dbo.F_Get_STR (@S VARCHAR(100))
RETURNS VARCHAR(100)
AS
BEGIN
WHILE PATINDEX('%[^a-z]%',@S)>0
BEGIN
set @s=stuff(@s,patindex('%[^a-z]%',@s),1,'')
END
RETURN @S
END
GO
--测试
select dbo.F_Get_STR('测试ABC123ABC')

GO

/*
功能:获取字符串中的数字
*/
create function dbo.F_Get_Number (@S varchar(100))
returns int
AS
begin
while PATINDEX('%[^0-9]%',@S)>0
begin
set @s=stuff(@s,patindex('%[^0-9]%',@s),1,'')
end
return cast(@S as int)
end
--测试
---select dbo.F_Get_Number('测试AB3C123AB5C')
GO