取得上周一和上周日sql语句

作者:袖梨 2022-06-29

获取上一周


-- 上周一的

 代码如下 复制代码

select title from info where DATEDIFF(DD,DATEADD(DW,-6-DATEPART(DW,getdate()),getdate()),title_date)=0;


获取上周一

把titleddtime改成你的字段名字啊

 代码如下 复制代码

select * from info 
where  DATEDIFF(dd,DATEADD(day,-7,DATEADD(week, DATEDIFF(week, '', getdate()), '')),titleddtime) =0
or
  DATEDIFF(dd,DATEADD(day,-5,DATEADD(week, DATEDIFF(week, '', getdate()), '')),titleddtime) =0
or
  DATEDIFF(dd,DATEADD(day,-3,DATEADD(week, DATEDIFF(week, '', getdate()), '')),titleddtime) =0

上周一与上周日sql语句

 代码如下 复制代码

SET DATEFIRST 1
DECLARE @day1 DATETIME
DECLARE @day7temp DATETIME
DECLARE @day7 VARCHAR(100)
SET @day1 = convert(char(10),dateadd(dd, - DATEPART (weekday , getdate())-6,getdate()),120)
SET @day7temp = convert(char(10),dateadd(dd, - DATEPART (weekday , getdate()),getdate()),120)
SET @day7 = CAST(YEAR(@day7temp) AS VARCHAR(4)) + '-' + CAST(MONTH(@day7temp) AS VARCHAR(2)) + '-' + CAST(DAY(@day7temp) AS VARCHAR(2)) + ' 23:59:59'
select  @day1
select @day7

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